Year 11 General Mathematics

Simultaneous Equations: Substitution and Elimination

Two equations. Two unknowns. One ordered pair that makes both of them work.

By the end of this lesson, you should be able to explain what a simultaneous solution means, solve pairs of linear equations using substitution and elimination, and decide which method is easier for a given pair of equations.

Getting started

One unknown is usually enough trouble. Today, we are dealing with two.

In this lesson, you will solve problems where two unknown values are connected by two equations. Your job is to find the pair of values that makes both equations true.

For example, if the unknowns are x and y, the final answer will usually look like this:

(x, y)

This pair is called the solution.

The important rule is simple: the answer has to work in both equations, not just one. If it only works in one equation, it is close-ish, but not the answer.

One equation

x + y = 10

Many pairs work, such as (6, 4) and (8, 2).

Two equations together

x + y = 10 x - y = 2

Now the pair must work in both equations. The pair (6, 4) works.

Checkpoint

Check that (6, 4) works in both equations above. Write one line for each equation.

This browser is blocking local storage, so scratchpad text cannot persist after the page is closed.
Question history and scratchpads reset.
Scratchpad note: Text typed here is saved only on this device. It is not submitted.

Substitution

Substitution means replacing one thing with another thing that has the same value. It is usually the easiest method when one equation already has x or y by itself.

What substitution is doing

If an equation says y = x + 4, then wherever you see y, you are allowed to write x + 4 instead. That turns two equations with two unknowns into one equation with one unknown.

  1. Find the equation where one variable is already by itself.
  2. Copy the other equation.
  3. Replace the isolated variable with the expression it equals.
  4. Solve the new one-variable equation.
  5. Put that answer back into either original equation to find the second value.
  6. Check both original equations.

Worked example Substitution when y is already by itself

Solve:

y = x + 4 2x + y = 10

Start with the equation that has y by itself:

y = x + 4

This means y and x + 4 are equal. In the second equation, replace y with x + 4.

2x + y = 10 2x + (x + 4) = 10

Now there is only x, so solve it like a normal linear equation.

2x + x + 4 = 10 3x + 4 = 10 3x = 6 x = 2

Use x = 2 to find y.

y = x + 4 y = 2 + 4 y = 6

Answer: (2, 6).

Check the answer
Equation A: y = x + 4 6 = 2 + 4 6 = 6 OK Equation B: 2x + y = 10 2(2) + 6 = 10 10 = 10 OK

Your turn

Solve using substitution. Show the replacement step clearly.

y = 3x - 1 x + y = 11
Hint: replace y with 3x - 1 in the second equation.
Check your solution
x + (3x - 1) = 11 4x - 1 = 11 4x = 12 x = 3 y = 3(3) - 1 y = 8 Solution: (3, 8)

Elimination

Elimination means making one variable disappear by adding or subtracting whole equations. It is usually the easiest method when the equations are already lined up, especially when one variable has matching or opposite coefficients.

What elimination is doing

If one equation has +y and another has -y, adding the equations makes the y terms cancel. If both equations have the same +2y, subtracting the equations makes the 2y terms cancel.

  1. Line up the x terms, y terms and numbers.
  2. Look for a variable that can cancel.
  3. Add if the signs are opposite, such as +y and -y.
  4. Subtract if the signs are the same, such as +2y and +2y.
  5. If nothing cancels yet, multiply one or both whole equations first.
  6. Solve, substitute back, and check.

Worked example Opposite terms are ready to cancel

Solve:

x + y = 9 x - y = 3

The equations contain +y and -y. Add the equations and the y terms cancel.

x + y = 9 + x - y = 3 ----------- 2x = 12 x = 6

Substitute x = 6 into one original equation.

x + y = 9 6 + y = 9 y = 3

Answer: (6, 3).

Worked example Multiply one equation first

Solve:

2x + y = 7 3x + 2y = 12

The first equation has y. The second equation has 2y. Multiply the whole first equation by 2 so both equations have 2y.

2(2x + y = 7) 4x + 2y = 14

Now subtract the second equation because both equations have +2y.

4x + 2y = 14 - 3x + 2y = 12 ------------- x = 2

Substitute x = 2 into the first original equation.

2x + y = 7 2(2) + y = 7 4 + y = 7 y = 3

Answer: (2, 3).

Your turn

Solve using elimination.

3x + y = 13 2x - y = 7
Hint: the y terms are already opposites, so add the equations.
Check your solution
3x + y = 13 + 2x - y = 7 ------------- 5x = 20 x = 4 3(4) + y = 13 12 + y = 13 y = 1 Solution: (4, 1)

The same answer on a graph

Every linear equation can be drawn as a straight line. A point on the blue line follows Equation A. A point on the green line follows Equation B. The red dot marks the intercept where the two lines meet, so that point follows both equations at the same time.

This lesson is about solving algebraically using substitution and elimination. The graph is included as a visual check. The full graphing method is part of another lesson on graphing simultaneous equations.

Type any ordered pair. The widget checks whether your point balances both equations.

Equation A Equation B Intercept Your tested point
Algebra shown for the selected example

Choosing a method

Both methods can give the same answer. The trick is choosing the method that makes the work easier for the equations in front of you.

A decision making table

What you see Try this Why
Already says x = ... or y = ... Substitution One variable is ready to replace.
Easy to make x = ... or y = ... Substitution Rearrange first, then replace.
Opposite terms, like +y and -y Elimination: add Opposites make zero.
Matching terms, like +2y and +2y Elimination: subtract Same terms subtract to zero.
Nothing cancels yet Elimination: multiply first Make a matching term, then cancel.
Example: choose substitution

Use substitution when one equation already has a variable by itself.

y = x + 4 2x + y = 10

Since y already equals x + 4, replace y in the second equation.

Example: choose elimination

Use elimination when the equations are lined up and a variable can cancel.

x + y = 9 x - y = 3

The +y and -y cancel if you add the equations.

Example: multiply first

Sometimes nothing cancels straight away.

2x + y = 7 3x + 2y = 12

The first equation has y. The second has 2y. Multiply the first equation by 2 to make the y terms match.

Practice

Open one section at a time. For each question, choose a method, solve the equations, and check your answer in at least one original equation.

Use New questions for a fresh set.

Practice tools

Substitution practice

Use substitution. Each question has one variable already by itself.

Check answers
    Elimination practice

    Use elimination. One variable can be cancelled by adding or subtracting the equations.

    Check answers
      Elimination with multiplying first

      Use elimination, but multiply one equation first so one variable can cancel.

      Check answers
        Mixed method practice

        Choose substitution or elimination. Write why you chose that method before solving.

        Check answers

          Extension challenge

          First, solve a tougher pair of equations. Then make your own pair and check that your chosen solution works in both.

          Part A: solve

          Solve this pair of equations. You may use substitution or elimination, but you should explain why your method makes sense.

          3x + 2y = 23 4x - 3y = 8

          Part B: create

          Create two new pairs of simultaneous equations with the same solution as Part A.

          1. Make one pair that is best solved by substitution.
          2. Make one pair that is best solved by elimination.
          3. Check that your solution works in both pairs.
          Extension answer
          Part A: 3x + 2y = 23 4x - 3y = 8 Multiply the first equation by 3: 9x + 6y = 69 Multiply the second equation by 2: 8x - 6y = 16 Add: 17x = 85 x = 5 Use 3x + 2y = 23: 3(5) + 2y = 23 15 + 2y = 23 2y = 8 y = 4 Solution: (5, 4) Example substitution pair with the same solution: y = x - 1 2x + y = 14 Example elimination pair with the same solution: 3x + 2y = 23 4x - 2y = 12

          Exit ticket

          Complete these before the end of the lesson.

          Explain

          In your own words, what does the solution to simultaneous equations represent?

          Solve by substitution

          y = 2x - 3 x + y = 12

          Solve by elimination

          2x + y = 11 3x - y = 9
          Exit ticket answers
          • The solution is the ordered pair that makes both equations true at the same time.
          • Substitution problem: (5, 7).
          • Elimination problem: (4, 3).
          Last check: put your ordered pair back into the original equations. It should make both equations true. If it does not, check for a sign error or arithmetic slip.